Converting a peptide's mass-per-volume concentration into molarity takes one value from the Certificate of Analysis, the molecular weight, and a short calculation. This guide walks through a full worked example.
What you need
You need the prepared concentration in mass-per-volume (mg/mL) and the peptide's molecular weight (MW) in grams per mole (g/mol), which appears on the COA.
The formula
Molarity (mol/L) = concentration (g/L) ÷ molecular weight (g/mol). Because 1 mg/mL equals 1 g/L, you can use the mg/mL number directly as g/L.
The worked example
Suppose you prepared a solution at 2 mg/mL and the peptide's molecular weight is 1,000 g/mol. Then: molarity = 2 g/L ÷ 1,000 g/mol = 0.002 mol/L = 2 millimolar (mM) = 2,000 micromolar (µM). If an assay calls for 10 µM, you would dilute this stock 200-fold.
Why the molecular weight matters
The same mass-per-volume corresponds to different molarities for peptides of different sizes, because a heavier molecule means fewer molecules in the same mass. That is why the conversion always depends on the molecular weight.
Related research guides
- Peptide concentration math guide
- mg/mL and molarity explained
- Stock & working solutions (serial dilution)
Research-use note
This describes laboratory concentration math for in vitro research use only.
Related research: Concentration calculator mg per mL and molarity.








