Lyophilized peptide vial beside a glass volumetric flask and graduated cylinder on a white lab bench, representing tesamorelin stock concentration calculations.
Mindful Research

Tesamorelin 10 mg / 5 mg Vials: Stock Concentration Math (In Vitro)

By: Mindful Research Team2 min read

Key takeaways

  • 10 mg of tesamorelin at 5195.908 g/mol is about 1.92 micromoles of peptide.
  • Stock concentration depends only on solvent volume: 10 mg in 1 mL is 10 mg/mL or about 1.92 mM.
  • A 5 mg amount in 1 mL gives 5 mg/mL or about 0.96 mM.
  • Dilute to assay concentrations with C1V1 = C2V2 and correct for net peptide content from the COA.
  • For in vitro research use only.

A tesamorelin 10 mg vial contains about 1.92 micromoles of peptide (10 mg divided by 5195.908 g/mol), so the stock concentration is set entirely by the solvent volume: 10 mg in 1 mL gives 10 mg/mL, or about 1.92 mM. This guide works through the arithmetic for Tesamorelin for in vitro assay preparation, and includes 5 mg values for researchers working from a smaller weighed amount. For the peptide itself see the tesamorelin structure and in-vitro research profile.

How do you convert mg per mL to molarity?

Molarity (mol/L) equals mass concentration (g/L) divided by molecular weight (g/mol). With the listed molecular weight of 5195.908 g/mol, 1 mg/mL equals 1 g/L, which is 0.192 mM. Happy Peptides lists tesamorelin as a 10 mg vial; the 5 mg column below applies when working from a different vial format or a smaller weighed amount of material.

What stock concentrations result from common solvent volumes?

Solvent volume 10 mg (mg/mL) 10 mg (mM) 5 mg (mg/mL) 5 mg (mM)
1 mL 10.0 1.92 5.0 0.96
2 mL 5.0 0.96 2.5 0.48
3 mL 3.33 0.64 1.67 0.32
5 mL 2.0 0.38 1.0 0.19
10 mL 1.0 0.19 0.5 0.10

How do you dilute a stock to assay concentrations?

Use C1 x V1 = C2 x V2. A 1.92 mM stock diluted 1:100 in assay buffer gives 19.2 micromolar; further 1:10 or half-log steps carry the series into the nanomolar and picomolar range needed to define a full concentration-response curve in a GHRH-receptor cAMP assay. Keep final solvent content identical across every well, including the vehicle control. A suitable aqueous solvent such as Reconstitution Solution is a common choice for aqueous stocks; follow the solvent's own documentation, and the solvent trade-offs are covered in why some peptides will not dissolve.

What affects the accuracy of the math?

  • Which molecular weight you use: the listed 5195.908 g/mol corresponds to the acetate form. The parent peptide is about 5135.9 g/mol, which would give 1.95 micromoles per 10 mg, a difference of roughly 1.2%.
  • Net peptide content: lyophilized powder includes counter-ions and residual water, so true peptide mass is below the label mass. Use the content figure from the certificate of analysis where it is provided.
  • Handling: prepare single-use aliquots and use low-bind plastic, since a 44-residue peptide can adsorb to surfaces at low concentrations.

Related research guides

Research-use note

All materials discussed are supplied for in vitro laboratory research use only, and are not for human or animal use.

Frequently asked questions

What is the molarity of a tesamorelin 10 mg vial in 1 mL?

A tesamorelin 10 mg vial contains about 1.92 micromoles (10 mg divided by 5195.908 g/mol), so 10 mg in 1 mL is 10 mg/mL, or about 1.92 mM. View Tesamorelin

What is the stock concentration for a 5 mg amount in 1 mL?

A 5 mg amount in 1 mL is 5 mg/mL, or about 0.96 mM, using 5195.908 g/mol.

How do I convert mg/mL to millimolar for tesamorelin?

Divide the concentration in g/L by 5195.908 g/mol; 1 mg/mL equals about 0.192 mM.

Why might the true concentration differ from the calculation?

Lyophilized peptide contains counter-ions and residual water, so net peptide content can be below the label mass; use the COA content figure. Tesamorelin COA and cost factors

Is it for human or animal use?

No. It is supplied for in vitro laboratory research use only.